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How Many Aliens Are There? The Drake Equation and the Fermi Paradox

Prerequisite:Dark Matter and Dark Energy: 95% of the Universe Has Only a Name So Far

Raw
  • The Drake equation writes the number NN of civilizations in the Galaxy that are communicating right now as a product of seven factors. The equation itself is essentially correct and follows from the definitions; the hard part is the values of the factors.
  • Even with plausible inputs, NN ranges from a few down to 10810^{-8}. Uncertainties in a product add up in the logarithm, so the answer is bound to swing by orders of magnitude.
  • The heart of the paradox is not that “we hear no radio”. Even a ship travelling at about 1 % of the speed of light needs only some 20 million years to spread across the whole Galaxy, and that is 0.15 % of the age of the Galaxy.
  • Conversely, hearing nothing means almost nothing. An Arecibo-class transmitter is detectable out to roughly 1000 light-years, and for even one civilization to lie inside that radius the Galaxy would have to hold about ten thousand civilizations simultaneously.
  • Candidate answers fall into four families — “nobody is there”, “they died”, “they are silent”, “we have not noticed” — and each carries predictions that future observations can separate.

Summer 1950, Los Alamos National Laboratory. On the way to lunch with his colleagues Emil Konopinski, Edward Teller and Herbert York, Enrico Fermi was discussing a cartoon that had appeared in The New Yorker. Public trash cans were disappearing from New York City at the time, and the cartoonist had pinned the blame on aliens carrying them off. The conversation drifted to flying saucers and faster-than-light travel, and then moved on to other things.

Some way into the meal, Fermi, who had been silent, is said to have suddenly asked:

Where is everybody?

According to the careful record assembled from the recollections of those present, Fermi then did one of his celebrated mental estimates on the spot and concluded that planets like the Earth cannot be rare, that on some of them life should become intelligent, that some of those should take up interstellar travel, and that they should therefore have reached the Earth long ago. Everyone thought “yes, quite” — and nobody had an answer.

The aim of this article is to translate that lunchtime aside into a problem that can be pinned down with numbers. Once the translation is done, something surprising happens. The question “are there aliens?” turns, for the most part, into questions of biology and social science, and what physics can answer stands out sharply. And the part physics can answer gives a strikingly definite conclusion.

This is not, incidentally, the first famous cosmic paradox. “Why is the night sky dark?” has exactly the same structure: knock down the naive assumptions one at a time and the shape of the universe emerges. For that one, read Why Is the Night Sky Dark?. The contradiction that follows from the naive assumptions is collected there as Olbers' paradox(Theorem 3.4)[Why Is the Night Sky Dark? Olbers' Paradox and the Finite Age of the Universe].

2. Preliminaries: getting a feel for the size and the timescales of the Galaxy

Section titled “2. Preliminaries: getting a feel for the size and the timescales of the Galaxy”

Let us first line up the numbers we will use again and again.

QuantityApproximate value
Number of stars in the Galaxy1×10111 \times 10^{11}4×10114 \times 10^{11}
Diameter of the galactic diskabout 100,000100{,}000 light-years
Thickness of the disk (thin disk)about 10001000 light-years
Sun to galactic centreabout 26,00026{,}000 light-years
Age of the oldest stars in the Galaxyabout 1313 billion years
Age of the Solar Systemabout 4.64.6 billion years
Time since life appeared on Earthabout 44 billion years
Time since multicellular life appearedabout 600600 million years
Time since Homo sapiens appearedabout 300,000300{,}000 years
Time since humans began emitting strong radioabout 9090 years

Numbers alone do not convey scale, so let us build a model. Shrink the 100,000100{,}000 light-year diameter of the Galaxy down to 11 metre. Then 11 light-year is 10 μm10\ \mu\mathrm{m}.

  • The 4.24.2 light-years to the nearest star, Proxima Centauri, becomes 42 μm42\ \mu\mathrm{m} — half the thickness of a human hair (about 80 μm80\ \mu\mathrm{m}).
  • The Solar System (out to Neptune’s orbit) is about 0.0010.001 light-years across, so 10 nm10\ \mathrm{nm}: one tenth the size of a virus.

So: on a disk one metre wide, a few hundred billion solar systems smaller than viruses are scattered at intervals about the thickness of a hair. That is the Galaxy. This model will pay off later, when we ask how far away we can be heard.

In 1959, Giuseppe Cocconi and Philip Morrison of Cornell University published a short paper in Nature. It asked which wavelength it would be rational to use for communication with a distant civilization. Their answer was the 21 cm21\ \mathrm{cm} line of atomic hydrogen, at a frequency of 1420 MHz1420\ \mathrm{MHz}. The reasoning is transparent: every astronomer anywhere in the universe knows that frequency, and it sits in the band where the galactic background noise is lowest. Without knowing anything about the other party, you make “something they must also know” your meeting place.

The following year, in 1960, the young radio astronomer Frank Drake pointed a 26 m26\ \mathrm{m} dish at Tau Ceti and Epsilon Eridani. This was Project Ozma. Nothing was found. Then in 1961 Drake convened a small meeting of eleven people at Green Bank. To organize the agenda, he wrote the following on the blackboard.

Definition 3.1The Drake equation

Let NN be the number of technological civilizations in the Galaxy that are, right now, emitting signals we could detect. Introduce the following seven quantities.

  • RR_{*}: the rate at which new stars form in the Galaxy (units: stars per year)
  • fpf_p: the fraction of those stars that have planetary systems (dimensionless, 0fp10 \le f_p \le 1)
  • nen_e: the average number of bodies per planetary system with an environment where life could survive (dimensionless, ne0n_e \ge 0)
  • ff_{\ell}: the fraction of such bodies on which life actually arises
  • fif_i: the fraction of life-bearing bodies on which life evolves all the way to intelligence
  • fcf_c: the fraction of intelligent species that acquire a technology emitting signals detectable across space
  • LL: the length of time such a civilization keeps emitting signals (units: years)

Then

N=RfpneffifcLN = R_{*} \cdot f_p \cdot n_e \cdot f_{\ell} \cdot f_i \cdot f_c \cdot L

holds. This is called the Drake equation.

flowchart TD
A["Stars born: R* per year"] --> B["Have planetary systems: fraction f_p"]
B --> C["Habitable bodies: n_e per system"]
C --> D["Life arises: fraction f_l"]
D --> E["Intelligence reached: fraction f_i"]
E --> F["Communication technology: fraction f_c"]
F --> G["Alive simultaneously: lifetime L years"]
The Drake equation reads as a funnel: it sieves the number of stars six times and leaves the number of civilizations alive right now

3.2. Why the lifetime LL appears as the last factor

Section titled “3.2. Why the lifetime LLL appears as the last factor”

The hardest part of the equation to swallow is that final LL. Multiplying fractions together makes sense, but why does multiplying by a lifetime give “the number in existence right now”? This can be proved properly.

Proposition 3.2A steady-state population equals birth rate times lifetime

Suppose civilizations are born at a constant rate RR (units: per year), and that every civilization born emits signals for exactly LL years and then stops. If this situation has persisted for a long time TLT \gg L, then the average number NN of civilizations signalling at any given moment is

N=RLN = R \cdot L
Proof(Proposition 3.2)

Consider an observing window of length TT. By definition, RTRT civilizations are born during this window.

Each civilization signals for LL years, so a single civilization contributes LL years of “civilization alive” to the window. The total over the whole window is therefore

(RT)×L=RTL[civilizationyears](RT) \times L = RTL \quad [\text{civilization} \cdot \text{years}]

(edge effects — the civilizations straddling the beginning and the end of the window — amount to a relative error of order L/TL/T, which is negligible because TLT \gg L).

On the other hand, this same total is the integral over time of “the number alive at each instant”. Writing its time average as NN, the total is NTN \cdot T. Equating the two,

NT=RTLN=RLN T = R T L \quad \Longrightarrow \quad N = R L

The part RfpneffifcR_{*} f_p n_e f_{\ell} f_i f_c of Definition 3.1 is precisely “how many communicating civilizations are newly born per year”. Identifying that with RR, the Drake equation is exactly this proposition.

This proposition is the same relation that queueing theory calls Little’s law. If two people per minute enter a noodle shop and each stays 15 minutes, there are on average 30 people inside. That is all there is to it. The last six factors of the Drake equation exist to estimate the “arrival rate”; the essential content is N=RLN = RL.

Example 3.3Two calculations, optimistic and pessimistic

The optimistic set. The present star formation rate of the Galaxy is roughly 1.51.533 solar masses per year, so take R=2R_{*} = 2 per year. Exoplanet surveys show that stars with planets are the rule rather than the exception, so fp=1f_p = 1. Kepler statistics suggest that some 10102020 % of Sun-like stars have an Earth-sized planet in the habitable zone, so take ne=0.2n_e = 0.2. The rest is pure guesswork, but suppose life arises reasonably often once the conditions are met, f=0.1f_{\ell} = 0.1; that the road to intelligence is narrower, fi=0.1f_i = 0.1; that a tenth of those take up radio, fc=0.1f_c = 0.1; and that the lifetime is L=104L = 10^{4} years.

N=2×1×0.2×0.1×0.1×0.1×104=2×0.2×103×104=4.\begin{aligned} N &= 2 \times 1 \times 0.2 \times 0.1 \times 0.1 \times 0.1 \times 10^{4} \\ &= 2 \times 0.2 \times 10^{-3} \times 10^{4} \\ &= 4 . \end{aligned}

Four in the Galaxy. This is the typical answer of the “aliens exist” camp.

The pessimistic set. Start from the same R=2R_{*} = 2 and fp=1f_p = 1, but suppose that a “genuinely stable long-term environment” is rare, ne=0.02n_e = 0.02; that the origin of life is chemically very hard indeed, f=103f_{\ell} = 10^{-3}; that the road from the eukaryotic cell to intelligence is narrower still, fi=104f_i = 10^{-4}; that fc=0.1f_c = 0.1; and that civilizations destroy themselves with their own technology after about 100100 years, L=100L = 100 years.

N=2×1×0.02×103×104×0.1×100=4×102×107×101=4×108.\begin{aligned} N &= 2 \times 1 \times 0.02 \times 10^{-3} \times 10^{-4} \times 0.1 \times 100 \\ &= 4 \times 10^{-2} \times 10^{-7} \times 10^{1} \\ &= 4 \times 10^{-8} . \end{aligned}

One civilization per 2525 million galaxies. With about 22 trillion galaxies in the observable universe, that gives some hundred thousand civilizations in the universe as a whole — and no chance whatsoever of our meeting one.

The same equation, both times with numbers that sound like “well, maybe”, gives 44 and 4×1084 \times 10^{-8}: a difference of eight orders of magnitude. This is not an arithmetic error; it is the nature of the equation. The next section makes the reason explicit.

Remark 3.4

Drake himself said repeatedly that the equation is not a tool for producing an answer but “a way of organizing our ignorance”. Its value lies in having cut one enormous mystery, NN, into smaller mysteries that separate disciplines can attack: astronomy (R,fp,neR_{*}, f_p, n_e), biology (f,fif_{\ell}, f_i) and social science (fc,Lf_c, L). And indeed, fpf_p and nen_e, completely unknown in 1961, are now pinned down observationally to within an order of magnitude. More than 50005000 exoplanets have been confirmed. From the left, the fog really is lifting.

4. The trap in a product: the mean is not the typical value

Section titled “4. The trap in a product: the mean is not the typical value”

If seven quantities are multiplied together and each might be off by “oh, a factor of ten or so”, how far off is the product?

To measure the “order of magnitude” of a number we use the common logarithm. Taking log10\log_{10} turns multiplication into addition, which simplifies matters.

Proposition 4.1In logarithms, uncertainties propagate in quadrature

Let N=x1x2xkN = x_1 x_2 \cdots x_k, where x1,,xkx_1, \ldots, x_k are mutually independent positive random variables. Let Yi=log10xiY_i = \log_{10} x_i have mean μi\mu_i and standard deviation σi\sigma_i. Then the mean and standard deviation of Y=log10NY = \log_{10} N are

E[Y]=i=1kμi,sd[Y]=i=1kσi2E[Y] = \sum_{i=1}^{k} \mu_i, \qquad \mathrm{sd}[Y] = \sqrt{\sum_{i=1}^{k} \sigma_i^{2}}

In particular, if all the σi\sigma_i equal a common value σ\sigma, then sd[Y]=σk\mathrm{sd}[Y] = \sigma\sqrt{k}.

Proof(Proposition 4.1)

Repeated use of log10(ab)=log10a+log10b\log_{10}(ab) = \log_{10}a + \log_{10}b gives

Y=log10(x1x2xk)=i=1klog10xi=i=1kYiY = \log_{10}(x_1 x_2 \cdots x_k) = \sum_{i=1}^{k} \log_{10} x_i = \sum_{i=1}^{k} Y_i

The mean (expectation) is linear on sums, that is, E[A+B]=E[A]+E[B]E[A+B] = E[A]+E[B] holds without assuming independence, so E[Y]=iE[Yi]=iμiE[Y] = \sum_i E[Y_i] = \sum_i \mu_i follows.

For the variance, in the case of two variables

V[Y1+Y2]=V[Y1]+V[Y2]+2Cov(Y1,Y2)V[Y_1 + Y_2] = V[Y_1] + V[Y_2] + 2\,\mathrm{Cov}(Y_1, Y_2)

holds in general. If Y1Y_1 and Y2Y_2 are independent, the covariance Cov(Y1,Y2)\mathrm{Cov}(Y_1,Y_2) vanishes, so V[Y1+Y2]=V[Y1]+V[Y2]V[Y_1+Y_2] = V[Y_1]+V[Y_2]. Applying this repeatedly to kk variables gives V[Y]=iσi2V[Y] = \sum_i \sigma_i^{2}. The standard deviation is the positive square root of the variance, so sd[Y]=iσi2\mathrm{sd}[Y] = \sqrt{\sum_i \sigma_i^2}.

If all σi=σ\sigma_i = \sigma, then kσ2=σk\sqrt{k\sigma^2} = \sigma\sqrt{k}.

Apply this to Definition 3.1. Here k=7k = 7, and suppose each factor is uncertain by “a factor of ten”, that is, σi=1\sigma_i = 1 order of magnitude. Then

sd[log10N]=72.65 orders of magnitude\mathrm{sd}[\log_{10} N] = \sqrt{7} \approx 2.65 \ \text{orders of magnitude}

The band of ±1\pm 1 standard deviation — the perfectly ordinary range — already spans 2×2.65=5.32 \times 2.65 = 5.3 orders of magnitude, a factor of 200,000200{,}000. The eight orders of magnitude in Example 3.3 arose because ff_{\ell} and fif_i are uncertain by far more than a single order; if anything, that example was restrained.

4.2. “Twenty on average” and “zero half the time” are compatible

Section titled “4.2. “Twenty on average” and “zero half the time” are compatible”

There is something worse. When uncertain quantities are multiplied, the expectation is not the typical value.

Proposition 4.2The arithmetic mean is at least the geometric mean

Let NN be a random variable taking each of the positive values N1,N2,,NmN_1, N_2, \ldots, N_m with probability 1/m1/m. Then

E[N]  =  1mj=1mNj    (j=1mNj)1/m  =  10E[log10N]E[N] \;=\; \frac{1}{m}\sum_{j=1}^{m} N_j \;\ge\; \left(\prod_{j=1}^{m} N_j\right)^{1/m} \;=\; 10^{\,E[\log_{10} N]}

holds, with equality if and only if N1=N2==NmN_1 = N_2 = \cdots = N_m.

Proof(Proposition 4.2)

First check the rightmost equality. Since E[log10N]=1mjlog10Nj=1mlog10(jNj)E[\log_{10}N] = \frac{1}{m}\sum_j \log_{10} N_j = \frac{1}{m}\log_{10}\left(\prod_j N_j\right), raising 1010 to both sides gives

10E[log10N]=101mlog10(jNj)=(jNj)1/m10^{\,E[\log_{10}N]} = 10^{\frac{1}{m}\log_{10}(\prod_j N_j)} = \left(\prod_{j} N_j\right)^{1/m}

which is the geometric mean.

The remaining inequality is the AM–GM inequality itself. The case m=2m = 2 can be verified directly: for a,b>0a, b > 0,

a+b2ab=a2ab+b2=(ab)22  0\frac{a+b}{2} - \sqrt{ab} = \frac{a - 2\sqrt{ab} + b}{2} = \frac{(\sqrt{a}-\sqrt{b})^{2}}{2} \ \ge\ 0

with equality only when a=b\sqrt a = \sqrt b, that is, a=ba = b. The same inequality (AM–GM) is known to hold for general mm, again with equality only when all the values coincide.

Example 4.3When the probability of life arising is a coin flip

Take the optimistic set of Example 3.3 and treat ff_{\ell} alone as follows. The origin of life is a problem of chemistry, and we have no idea how hard it is. So suppose it is either “essentially certain once conditions allow (f=1f_{\ell} = 1)” or “so hard that there is hardly another instance in the universe (f=1010f_{\ell} = 10^{-10})”, each with probability one half.

The optimistic set used f=0.1f_{\ell} = 0.1 and gave N=4N = 4, and NN is proportional to ff_{\ell}, so

N={4×10.1=40(probability 1/2)4×10100.1=4×109(probability 1/2)N = \begin{cases} 4 \times \dfrac{1}{0.1} = 40 & (\text{probability } 1/2) \\[2mm] 4 \times \dfrac{10^{-10}}{0.1} = 4\times 10^{-9} & (\text{probability } 1/2) \end{cases}

The expectation is

E[N]=40+4×109220E[N] = \frac{40 + 4\times10^{-9}}{2} \approx 20

But by Proposition 4.2 the geometric mean is

40×4×109=1.6×107=4×104\sqrt{40 \times 4\times10^{-9}} = \sqrt{1.6\times10^{-7}} = 4\times10^{-4}

which is only one fifty-thousandth of the expectation. And looking inside, half the time the Galaxy contains nobody but us. The statement “the Galaxy contains on average 20 civilizations” and the statement “if the coin comes up tails we are utterly alone” came out of exactly the same model.

Remark 4.4

Sandberg, Drexler and Ord carried this argument through carefully for all seven factors in their 2018 paper “Dissolving the Fermi Paradox”. Instead of point estimates, they assigned each factor a probability distribution spanning the range the current scientific literature allows, ran millions of Monte Carlo samples, and obtained a probability of 53 – 99.6 % that we are alone in the Galaxy, and 39 – 85 % that we are alone in the observable universe. Their claim is not “there are no aliens” but “once uncertainty is handled properly, there was never much reason to be surprised by silence”. Half the paradox, on this view, was an illusion manufactured by the bad habit of using point estimates.

5. The paradox stated precisely: why “nobody comes” is the problem

Section titled “5. The paradox stated precisely: why “nobody comes” is the problem”

We have now seen that a small NN is nothing to wonder at. So has Fermi’s question been answered? It has not. The genuinely sharp part of the paradox has nothing to do with radio at all.

5.1. The time it takes to cross the Galaxy

Section titled “5.1. The time it takes to cross the Galaxy”

Picture a ship hopping from star to star. Each civilization sends ships to nearby systems; on arrival they gather resources, get established, and from there launch ships to the next systems. Let us compute how fast this wave spreads.

Proposition 5.1The spreading time of a colonization wave

Suppose a civilization spreads from star system to star system by the following rule.

  • Each hop covers a distance dd (the mean distance to the neighbouring system).
  • Ships travel at a constant speed vv.
  • After arriving at a new system, a preparation time τ\tau elapses before the next ship departs.

Then the time TT for the wave to reach a point at distance DD from the starting point is

T=Dd(dv+τ)=Dv+DdτT = \frac{D}{d}\left(\frac{d}{v} + \tau\right) = \frac{D}{v} + \frac{D}{d}\,\tau

and the effective speed of the wavefront veff=D/Tv_{\mathrm{eff}} = D/T is

veff=ddv+τ=v1+vτdv_{\mathrm{eff}} = \frac{d}{\dfrac{d}{v} + \tau} = \frac{v}{1 + \dfrac{v\tau}{d}}

In particular, veffv_{\mathrm{eff}} does not depend on DD.

Proof(Proposition 5.1)

Dividing the distance DD by the hop length dd, the number of hops required is n=D/dn = D/d.

One hop takes the flight time d/vd/v plus the preparation time τ\tau on arrival, so d/v+τd/v + \tau. The hops occur in series one after another, so the total time for nn hops is

T=n(dv+τ)=Dd(dv+τ)T = n\left(\frac{d}{v}+\tau\right) = \frac{D}{d}\left(\frac{d}{v}+\tau\right)

Expanding the bracket gives T=D/v+(D/d)τT = D/v + (D/d)\tau.

The effective speed is by definition veff=D/Tv_{\mathrm{eff}} = D/T, so substituting the above TT,

veff=DDd(dv+τ)=ddv+τv_{\mathrm{eff}} = \frac{D}{\dfrac{D}{d}\left(\dfrac{d}{v}+\tau\right)} = \frac{d}{\dfrac{d}{v}+\tau}

Dividing numerator and denominator by dd gives veff=v/(1+vτ/d)v_{\mathrm{eff}} = v/(1 + v\tau/d). Since DD does not appear in this expression, veffv_{\mathrm{eff}} is a constant independent of distance.

The real spreading is spherical rather than along a line, but the wavefront advances by the same rule in every direction, so the arrival time measured radially from the centre is exactly the calculation above.

Here is where it becomes interesting.

Corollary 5.2However fast the ships, the waiting time sets the limit

In the setting of Proposition 5.1, if vτdv\tau \gg d (equivalently d/vτd/v \ll \tau), then

veffdτ,TDdτv_{\mathrm{eff}} \approx \frac{d}{\tau}, \qquad T \approx \frac{D}{d}\,\tau

In particular, even in the limit vv \to \infty (instantaneous travel), TT never falls below Ddτ\dfrac{D}{d}\tau.

Proof(Corollary 5.2)

In the expression veff=d/(d/v+τ)v_{\mathrm{eff}} = d/(d/v + \tau) from Proposition 5.1, the assumption d/vτd/v \ll \tau lets us approximate the denominator by τ\tau. Hence veffd/τv_{\mathrm{eff}} \approx d/\tau and T=D/veff(D/d)τT = D/v_{\mathrm{eff}} \approx (D/d)\tau.

More precisely, in T=D/v+(D/d)τT = D/v + (D/d)\tau the first term D/vD/v can be made as small as we like by increasing vv, but the second term (D/d)τ(D/d)\tau contains no vv at all. So in the limit vv \to \infty we get T(D/d)τT \to (D/d)\tau, and this is a lower bound.

The significance of this corollary is considerable. No warp drive and no antimatter engine is required. The waiting time τ\tau and the hop length dd alone fix a lower bound on the time to cross the Galaxy.

Example 5.3What modest numbers give

From the mean spacing of stars in the solar neighbourhood take d=10d = 10 light-years; let the ships travel at 1 % of light speed, v=0.01cv = 0.01c; and allow τ=1000\tau = 1000 years of preparation between arriving in a new system and launching the next ship. A thousand years means resting, every single time, for as long as it took humanity to get from the Middle Ages to the present. Taking the distance across the Galaxy as D=105D = 10^{5} light-years, Proposition 5.1 gives

Dv=105 ly0.01 ly/yr=107 years,Ddτ=10510×103=104×103=107 years,\begin{aligned} \frac{D}{v} &= \frac{10^{5}\ \text{ly}}{0.01\ \text{ly/yr}} = 10^{7}\ \text{years}, \\ \frac{D}{d}\tau &= \frac{10^{5}}{10}\times 10^{3} = 10^{4}\times10^{3} = 10^{7}\ \text{years}, \end{aligned}

and therefore

T=107+107=2×107 years=20 million yearsT = 10^{7} + 10^{7} = 2\times10^{7}\ \text{years} = 20\ \text{million years}

The effective speed is veff=105/(2×107)=5×103v_{\mathrm{eff}} = 10^{5}/(2\times10^{7}) = 5\times10^{-3} light-years per year, that is, 0.50.5 % of the speed of light.

Moreover, by Corollary 5.2, making the ships infinitely fast cannot bring TT below 10710^{7} years, or 10 million years. Conversely, stretching the preparation time to τ=104\tau = 10^{4} years (twice the whole recorded history of humanity) still only gives T=107+1081.1×108T = 10^{7} + 10^{8} \approx 1.1\times10^{8} years.

Compared with the age of the Galaxy, 1.3×10101.3\times10^{10} years, 2×1072\times10^{7} years is 0.150.15 %. Even 1.1×1081.1\times10^{8} years is only 0.850.85 %.

Age of the Galaxy: about 13 billion yearsSince life appeared on Earth: about 4 billion yearsTime for a civilization to cross the Galaxy: about 20 million yearsThis width is about 1 pixel: 0.15 % of the top bar
The time to cross the Galaxy against the age of the Galaxy. The horizontal axis is a common linear scale.

Definition 5.4The Fermi paradox

Consider the following four claims.

  1. The Galaxy contains many stars billions of years older than the Sun, and most of them have planetary systems.
  2. Even if the probability of life and intelligence arising is very small, there are 101110^{11} stars, so we should expect at least one case in which a technological civilization appeared hundreds of millions to billions of years before us.
  3. If interstellar travel is possible in principle, such a civilization can reach the whole Galaxy in 10710^{7} to 10810^{8} years, a tiny fraction of the age of the Galaxy (Proposition 5.1, Corollary 5.2).
  4. Yet neither in the Solar System nor on Earth has any trace of a visit by an extraterrestrial civilization, nor any of its machines or structures, ever been found.

The situation that claims 1 through 4 cannot all hold at once — that one of the premises must be false — is called the Fermi paradox.

Put this way, it becomes clear where the substance of the paradox lies. The problem is not that “we hear no radio” but that nobody has come. Michael Hart (1975) and Frank Tipler (1980) pushed this argument hard. Tipler further pointed out that if a civilization launches machines capable of building copies of themselves (von Neumann probes), then even after the civilization itself has perished the probes keep multiplying and fill the Galaxy. One probe builds two, each of those builds two more; repeat this 4040 times and you have 101210^{12} of them.

In short: if a single expansion-minded civilization arose even once, anywhere, during the 13 billion years of galactic history, its traces should be in the Solar System. That is the blade of the paradox.

6. What the silence means: how much have we actually listened to?

Section titled “6. What the silence means: how much have we actually listened to?”

Before turning to the blade, let us fix with numbers how weak the “we hear nothing” evidence is. This is the part physics answers cleanly.

Definition 6.1Detection horizon

Let PP be the equivalent isotropically radiated power (EIRP) of a transmitter. This is the power of a hypothetical transmitter that radiates the same signal strength uniformly in all directions; it is larger than the actual transmitted power by whatever factor the antenna concentrates the beam.

If SminS_{\min} (units: W/m2\mathrm{W/m^2}) is the smallest power flux density the receiver can detect, the maximum distance rmaxr_{\max} at which this transmitter can be detected is called the detection horizon.

Proposition 6.2The detection horizon scales as the square root of the power

When absorption of radio waves in interstellar space is negligible, the detection horizon of Definition 6.1 is

rmax=P4πSminr_{\max} = \sqrt{\frac{P}{4\pi S_{\min}}}

In particular, rmaxr_{\max} is proportional to P\sqrt{P}.

Proof(Proposition 6.2)

Consider a sphere of radius rr centred on the transmitter. By conservation of energy, in the absence of absorption the electromagnetic energy crossing this sphere per unit time equals PP regardless of distance. Since we have reduced everything to the isotropic equivalent, we may treat the flux as uniform over the sphere, whose area is 4πr24\pi r^{2}; the power crossing unit area (the power flux density) is therefore

S(r)=P4πr2S(r) = \frac{P}{4\pi r^{2}}

This is the inverse-square law(Proposition 2.2)[How We Know the Distance to a Star]. Detection requires S(r)SminS(r) \ge S_{\min}, that is,

P4πr2Sminr2P4πSminrP4πSmin.\frac{P}{4\pi r^{2}} \ge S_{\min} \quad\Longleftrightarrow\quad r^{2} \le \frac{P}{4\pi S_{\min}} \quad\Longleftrightarrow\quad r \le \sqrt{\frac{P}{4\pi S_{\min}}} .

The last equivalence uses r>0r > 0. The right-hand side is rmaxr_{\max}.

Note that in the 1110 GHz10\ \mathrm{GHz} band both absorption by the interstellar medium and the galactic background are small, which is why this band is called the “cosmic window”. It is also why Cocconi and Morrison chose 1420 MHz1420\ \mathrm{MHz}, and it makes neglecting absorption legitimate in this band.

Example 6.3How far does the Arecibo planetary radar reach?

The 305 m305\ \mathrm{m} dish of the Arecibo Observatory in Puerto Rico carried a powerful radar transmitter for observing asteroids. Its EIRP was about P=1013 WP = 10^{13}\ \mathrm{W}.

Assume a comparable telescope on the receiving end. Restricting to a narrow band (bandwidth of order 1 Hz1\ \mathrm{Hz}) and integrating for a long time gives a detection limit of roughly Smin=1026 W/m2S_{\min} = 10^{-26}\ \mathrm{W/m^2}. From Proposition 6.2,

rmax=10134π×1026=10131.26×1025=7.96×1037=8.9×1018 m.r_{\max} = \sqrt{\frac{10^{13}}{4\pi \times 10^{-26}}} = \sqrt{\frac{10^{13}}{1.26\times10^{-25}}} = \sqrt{7.96\times10^{37}} = 8.9\times10^{18}\ \mathrm{m} .

Dividing by 11 light-year =9.46×1015 m= 9.46\times10^{15}\ \mathrm{m},

rmax940 light-years1000 light-yearsr_{\max} \approx 940\ \text{light-years} \approx 1000\ \text{light-years}

That is only 1 % of the 100,000100{,}000 light-year diameter of the Galaxy. In the scale model of section 2, the region within earshot of us is a circle of radius 1 cm1\ \mathrm{cm} on a disk one metre across.

Incidentally, the Arecibo telescope collapsed under its own weight in December 2020. Humanity does not currently possess even the transmitting capability used in this calculation.

Example 6.4Is the Earth shouting into space?

One often hears that “Earth’s television broadcasts have spread out to a radius of 90 light-years”. They have spread, but whether anyone can hear them is another matter.

The effective radiated power of a strong UHF television transmitter is at most about P=107 WP = 10^{7}\ \mathrm{W}. Using Proposition 6.2 with the same Smin=1026 W/m2S_{\min} = 10^{-26}\ \mathrm{W/m^2},

rmax=1071.26×1025=7.96×1031=8.9×1015 m0.94 light-yearsr_{\max} = \sqrt{\frac{10^{7}}{1.26\times10^{-25}}} = \sqrt{7.96\times10^{31}} = 8.9\times10^{15}\ \mathrm{m} \approx 0.94\ \text{light-years}

It does not even reach one light-year. Put a telescope like ours at the nearest star, Proxima Centauri (4.24.2 light-years; how that distance is measured appears in the distance to the nearest star(Example 3.3)[How We Know the Distance to a Star]), and Earth’s television is inaudible. Worse, real television signals are broadband, so the sensitivity of narrowband searches does not apply, making the situation worse still.

So the intuition that “if aliens existed they would have noticed Earth’s radio long ago” is simply wrong. And human radio leakage is currently decreasing: terrestrial broadcasting is being replaced by optical fibre, and satellites by highly directional beams. If other civilizations follow the same path, the “time spent emitting radio” behind fcf_c and LL may be startlingly short.

6.1. How close would they have to be for us to hear them?

Section titled “6.1. How close would they have to be for us to hear them?”

Proposition 6.5Typical spacing of civilizations scattered through the galactic disk

Suppose NN civilizations are distributed roughly uniformly over a disk-shaped region of radius RgR_g. If the thickness of the disk is much smaller than the spacing between civilizations, the typical distance \ell between neighbouring civilizations is

RgπN\ell \approx R_g\sqrt{\frac{\pi}{N}}
Proof(Proposition 6.5)

Since the thickness of the disk is much smaller than the spacing, we may treat the distribution as a two-dimensional problem. The area of the disk is πRg2\pi R_g^{2}. Shared among NN civilizations, the area allotted to each is

A1=πRg2NA_1 = \frac{\pi R_g^{2}}{N}

Regarding this area as a square of side \ell gives 2=A1\ell^{2} = A_1, that is,

=πRg2N=RgπN\ell = \sqrt{\frac{\pi R_g^{2}}{N}} = R_g\sqrt{\frac{\pi}{N}}

For a completely random (two-dimensional Poisson) arrangement, the mean nearest-neighbour distance works out to 1/(2n)=/21/(2\sqrt{n}) = \ell/2 in terms of the number density n=N/(πRg2)n = N/(\pi R_g^{2}). That is half the estimate above, but the order of magnitude is unchanged. In what follows we use \ell, conscious of this factor-of-two ambiguity.

Corollary 6.6The silence is exactly what we should expect

Let rmaxr_{\max} be the detection horizon and RgR_g the radius of the galactic disk. For the nearest civilization to lie inside the detection horizon, that is, for rmax\ell \le r_{\max}, it is necessary that

N  πRg2rmax2N \ \ge\ \frac{\pi R_g^{2}}{r_{\max}^{2}}

For Rg=5×104R_g = 5\times10^{4} light-years and rmax=103r_{\max} = 10^{3} light-years, this condition reads N7.9×103N \ge 7.9\times10^{3}: it requires about ten thousand civilizations to exist in the Galaxy simultaneously.

Proof(Corollary 6.6)

By Proposition 6.5, =Rgπ/N\ell = R_g\sqrt{\pi/N}. The condition rmax\ell \le r_{\max} is equivalent to

RgπNrmaxπRg2Nrmax2NπRg2rmax2R_g\sqrt{\frac{\pi}{N}} \le r_{\max} \quad\Longleftrightarrow\quad \frac{\pi R_g^{2}}{N} \le r_{\max}^{2} \quad\Longleftrightarrow\quad N \ge \frac{\pi R_g^{2}}{r_{\max}^{2}}

(both sides are positive, so squaring does not reverse the inequality). Substituting the numbers,

Nπ×(5×104)2(103)2=π×2.5×109106=7.9×103N \ge \frac{\pi \times (5\times10^{4})^{2}}{(10^{3})^{2}} = \frac{\pi \times 2.5\times10^{9}}{10^{6}} = 7.9\times10^{3}

Including the Poisson correction mentioned in the proof of Proposition 6.5 (which halves \ell) gives N2×103N \ge 2\times10^{3} or so; the order of magnitude is unchanged.

Even the optimistic set of Example 3.3 gave only N=4N = 4. In that case the distance to the nearest civilization, from Proposition 6.5, is

=5×104×π4=5×104×0.8864.4×104 light-years\ell = 5\times10^{4}\times\sqrt{\frac{\pi}{4}} = 5\times10^{4}\times0.886 \approx 4.4\times10^{4}\ \text{light-years}

which is more than 4040 times the detection horizon. A round-trip message would take 90,00090{,}000 years. Even if the optimists are right, hearing nothing is the normal outcome for us.

Remark 6.7

There is also research quantifying the coverage of the search itself. In a 2018 paper, Wright, Kanodia and Lubar treated the SETI search space as a multidimensional haystack — direction on the sky, frequency, sensitivity, polarization, modulation and time — and evaluated what fraction of its volume humanity has actually examined. Their conclusion was that the fraction searched is a tiny sliver of the whole, comparable to a bathtub of water set against all the oceans of Earth. Even in the data the Breakthrough Listen programme released in 2020, the number of nearby stars examined carefully was 1327. That is 1327 out of 101110^{11} stars in the Galaxy.

The strong narrowband signal that the Big Ear telescope at Ohio State University caught for just 7272 seconds in 1977 (called the “Wow!” signal because its discoverer wrote that word in the margin of the printout) has never been seen again, however hard anyone has looked. What it was remains unknown.

So one of the four claims in Definition 5.4 is false. Which? Dozens of solutions have been proposed, but they sort into four broad families.

This position denies claim 2. In their 2000 book Rare Earth, Peter Ward and Donald Brownlee argued that while single-celled organisms may be commonplace, complex animals require an extraordinary number of conditions: a moon of the right size to stabilize the spin axis, Jupiter-class planets to sweep up comets, plate tectonics to run the carbon cycle, and a position in the Galaxy where radiation is not too intense and heavy elements not too scarce. If missing even one of these is fatal, then nen_e and fif_i become dramatically small.

Another version is the “we are first” hypothesis. The universe is still young. Sun-like stars live for 1010 billion years, but red dwarfs — 75 % of all stars — live for more than 101210^{12} years. Most of the “time suitable for life” that the universe will ever experience has not yet arrived. In a 2016 paper, Loeb and collaborators evaluated the probability of life as a function of cosmic time and argued that it peaks around low-mass stars far in the future. On this view we are guests who arrived at the cosmic party far too early, while the others are still getting ready.

Definition 7.1The Great Filter

Consider the sequence of steps leading from inanimate matter to a technological civilization spread across the Galaxy: planet formation, the origin of life, complex cells, multicellularity, intelligence, technology, expansion into space. Given that the Fermi paradox is a fact, somewhere along this sequence there must be a barrier with an extremely small probability of being passed. This barrier is called the Great Filter.

When the filter lies at a step earlier than humanity’s present position, we say it is behind us; when it lies at a later step, that it is ahead of us.

The concept was introduced by Robin Hanson in 1998. The logic is simple. The fact the paradox reveals — that the Galaxy is empty — implies that some point along the path is extremely narrow. We do not know where the narrow point is, but there must be one.

Here we reach the famous and unsettling consequence Nick Bostrom stated in 2008: if independently originated life were found on Mars or Europa, it would be bad news for humanity. The reasoning goes as follows. If the origin of life (ff_{\ell}) turns out to be easy, then the filter must lie after the origin of life, which raises the probability that it lies ahead of us. Conversely, if no second origin of life is found anywhere in the Solar System, the filter is more likely to be a barrier behind us, one we have already passed, and humanity’s future is bright. Astrobiology thereby becomes the strange discipline in which finding nothing is the reassuring outcome.

Candidates commonly proposed for a filter ahead of us include nuclear war, irreversible destruction of the environment, artificial intelligence that escapes control, and engineered pathogens. In short, the claim is that LL is short. As Example 3.3 shows, NN is proportional to LL, so whether the mean lifetime of a civilization is 100100 years or a million changes the answer by a factor of 10,00010{,}000. The rightmost factor of the Drake equation is a factor about ourselves.

This position rereads “no traces” in claim 4 as “traces are being kept from us”. The zoo hypothesis, proposed by John A. Ball in 1973, holds that we are treated like organisms in a nature reserve: observed, but with contact forbidden. David Brin organized and criticized hypotheses of this kind in a 1983 review.

A darker version is the dark forest hypothesis, made widely known by the novels of Liu Cixin. When you cannot know another party’s intentions, whoever reveals their position first is at a disadvantage; therefore every rational civilization stays silent. As a story it is superb; as a scientific hypothesis it has a weakness.

7.4. They are there, and we have not noticed

Section titled “7.4. They are there, and we have not noticed”

This position blames claim 4 on the limits of our searching. As Example 6.3 and Corollary 6.6 show, this position is overwhelmingly strong where radio is concerned. We can listen only out to about 1 % of the diameter of the Galaxy, and within that we have examined only a few thousand stars carefully. If they use lasers rather than radio, or some method we have not imagined, our net never had a chance of catching them.

Against claim 3 of Definition 5.4, however, this position is powerless. The structures of a civilization that has filled the Galaxy would be far harder to hide.

HypothesisCore ideaWhich part of the paradox it explainsObservations that could bear on it
Rare EarthThe conditions for complex life are extraordinarily strictne,f,fin_e, f_{\ell}, f_i are extremely smallSearches for atmospheric biosignatures on exoplanets
We are firstThe universe is young; the prime time for civilizations lies aheadExplains small NN by timingTheory of stellar lifetime distributions and cosmic chemical evolution
Great Filter (behind)The origin of life or of eukaryotes is exceedingly rareWhy nobody comesSearches for a second origin of life on Mars, Europa, Enceladus
Great Filter (ahead)Technological civilizations are short-livedWhy LL is smallOur own history (nuclear weapons, climate, AI)
Zoo hypothesisWe are observed but contact is forbiddenBoth the silence and the absenceHard to falsify; little predictive power
Dark forestExposure is suicide, so nobody transmitsThe silenceSearching for artefacts rather than transmissions
Poor searchingThe search space is vast and mostly unexploredThe silence onlySystematic expansion of the searched volume

Laid out this way, the structure of the question becomes visible. There is no shortage of hypotheses explaining the silence, and most of them become unnecessary the moment one accepts Corollary 6.6. What genuinely demands explanation is the absence: the fact that a Galaxy which should fill up in 10710^{7} years is empty. And the explanations for absence reduce, in practice, to three: “nobody is there in the first place”, “the Great Filter”, and “declining to expand is a universal choice”.

Fermi’s question is still open 7676 years later. But its shape has certainly grown sharper.

Exercise 8.1Easy

In Definition 3.1, hold every factor except LL fixed.

(1) If LL changes from 100100 years to 10610^{6} years, by what factor does NN change?

(2) For the optimistic set of Example 3.3 (L=104L = 10^{4} years, N=4N = 4), find NN when L=100L = 100 years.

Solution

(1) On the right-hand side of Definition 3.1, LL appears to the first power, so NN is proportional to LL. Hence the factor is

106100=104\frac{10^{6}}{100} = 10^{4}

that is, 10,00010{,}000.

(2) By proportionality,

N=4×100104=4×102=0.04N = 4 \times \frac{100}{10^{4}} = 4\times10^{-2} = 0.04

which means one civilization per 2525 galaxies.

However optimistic our estimates of the astronomical and biological factors, if a civilization emits radio for only 100100 years then the Galaxy effectively contains nobody but us. That is why the rightmost factor of the Drake equation is said to be “a question about ourselves”.

Exercise 8.2Standard

In the setting of Proposition 5.1, take D=105D = 10^{5} light-years, hop length d=20d = 20 light-years, preparation time τ=5000\tau = 5000 years, and ship speed v=0.1cv = 0.1c.

(1) Find the crossing time TT and the effective speed veffv_{\mathrm{eff}}.

(2) Find TT in the limit of infinitely fast ships (vv \to \infty) and compare with (1).

(3) What percentage of the age of the Galaxy, 1.3×10101.3\times10^{10} years, is the TT from (1)?

Solution

(1) Substitute into T=D/v+(D/d)τT = D/v + (D/d)\tau from Proposition 5.1. Since v=0.1c=0.1v = 0.1c = 0.1 light-years per year,

Dv=1050.1=106 years,\frac{D}{v} = \frac{10^{5}}{0.1} = 10^{6}\ \text{years},Ddτ=10520×5000=5000×5000=2.5×107 years.\frac{D}{d}\tau = \frac{10^{5}}{20}\times 5000 = 5000 \times 5000 = 2.5\times10^{7}\ \text{years}.

Hence

T=1.0×106+2.5×107=2.6×107 yearsT = 1.0\times10^{6} + 2.5\times10^{7} = 2.6\times10^{7}\ \text{years}

The effective speed is

veff=DT=1052.6×107=3.8×103 light-years/year=0.0038cv_{\mathrm{eff}} = \frac{D}{T} = \frac{10^{5}}{2.6\times10^{7}} = 3.8\times10^{-3}\ \text{light-years/year} = 0.0038\,c

The ships fly at 10 % of the speed of light, yet the wavefront advances at only 0.38 % of it.

(2) By Corollary 5.2, as vv \to \infty we get T(D/d)τ=2.5×107T \to (D/d)\tau = 2.5\times10^{7} years. Compared with the 2.6×1072.6\times10^{7} years of (1), that is a reduction of only 44 %. In this setting the waiting time already dominates, and improving the ships’ performance is pointless.

(3)

2.6×1071.3×1010=2.0×103=0.2 %\frac{2.6\times10^{7}}{1.3\times10^{10}} = 2.0\times10^{-3} = 0.2\ \%

The whole Galaxy fills up in 0.20.2 % of its history. Put the other way round: if an expansion-minded civilization had appeared at any moment in the past 13 billion years, its traces should have persisted through 99.899.8 % of that time.

Exercise 8.3Standard

Use Proposition 6.2, with the receiver’s detection limit fixed at Smin=1026 W/m2S_{\min} = 10^{-26}\ \mathrm{W/m^2}.

(1) If the transmitter’s EIRP is increased by a factor of 100100, by what factor does the detection horizon rmaxr_{\max} increase?

(2) Find the EIRP needed to reach the far side of the Galaxy (r=105r = 10^{5} light-years =9.46×1020 m= 9.46\times10^{20}\ \mathrm{m}).

(3) Compare the value from (2) with humanity’s total primary energy consumption, 2×1013 W2\times10^{13}\ \mathrm{W}. If the antenna gain is the same as Arecibo’s (EIRP is 10710^{7} times the actual transmitted power), what actual transmitted power is required?

Solution

(1) By Proposition 6.2, rmaxPr_{\max} \propto \sqrt{P}, so the factor is 100=10\sqrt{100} = 10. Distance is expensive: reaching 1010 times farther takes 100100 times the power.

(2) Solving rmax=P/(4πSmin)r_{\max} = \sqrt{P/(4\pi S_{\min})} for PP gives P=4πrmax2SminP = 4\pi r_{\max}^{2} S_{\min}. With rmax=9.46×1020 mr_{\max} = 9.46\times10^{20}\ \mathrm{m},

rmax2=8.95×1041 m2,4πrmax2=1.12×1043 m2,r_{\max}^{2} = 8.95\times10^{41}\ \mathrm{m^2}, \qquad 4\pi r_{\max}^{2} = 1.12\times10^{43}\ \mathrm{m^2},P=1.12×1043×1026=1.1×1017 W.P = 1.12\times10^{43} \times 10^{-26} = 1.1\times10^{17}\ \mathrm{W}.

(3) The ratio to humanity’s primary energy consumption is

1.1×10172×10135.6×103\frac{1.1\times10^{17}}{2\times10^{13}} \approx 5.6\times10^{3}

about 56005600 times all the energy humanity uses. But this is the isotropic equivalent; concentrating the beam with an antenna reduces the actual transmitted power a great deal. With a gain of 10710^{7},

Pactual=1.1×1017107=1.1×1010 W=11 billion WP_{\text{actual}} = \frac{1.1\times10^{17}}{10^{7}} = 1.1\times10^{10}\ \mathrm{W} = 11\ \text{billion}\ \mathrm{W}

roughly the output of ten large nuclear power stations. Technically that is not an impossible figure.

One caveat, though. Because the beam is narrow, it illuminates only one very small direction of the sky at a time. Running a permanent beacon aimed at the whole Galaxy would require as many transmitters as there are directions. This is the source of SETI’s basic asymmetry: listening is far cheaper than transmitting. And if everyone does that calculation and everyone chooses to listen, the universe stays quiet.

Exercise 8.4Hard

Suppose fossil microbes are found beneath the surface of Mars, and it is certain that they arose independently of life on Earth.

(1) Which factor of Definition 3.1 does this inform us about?

(2) Is this discovery good news or bad news for humanity’s future? Argue using the terms “behind” and “ahead” from Definition 7.1.

Solution

(1) It informs us about ff_{\ell}, the fraction of habitable bodies on which life actually arises. If life arose twice independently within a single planetary system, the natural conclusion is that ff_{\ell} is very large (close to 11).

(2) It is bad news. Let us take it step by step.

First, what Definition 5.4 establishes is the observational fact that the Galaxy is not filled with expanding civilizations. By Definition 7.1, this fact means that somewhere along the road from inanimate matter to a galactic civilization there is an extremely narrow barrier. That the barrier exists somewhere is not negotiable.

Next, suppose we learn that ff_{\ell} is large. Then the step “the origin of life” was not the narrow barrier. Since the barrier is somewhere, by elimination the probability rises that it lies in one of the remaining steps. Those are eukaryotic cells, multicellularity, intelligence, technology, and the long-term survival of a technological civilization. Of these, the only one humanity has not yet passed is the last. Hence the probability that the filter lies ahead of us rises.

Conversely, if no second origin of life is found anywhere in the Solar System, the possibility remains that ff_{\ell} is extremely small. In that case the filter is behind us, a barrier humanity has already passed, and the probability that one waits ahead goes down. This is the substance of Bostrom’s claim that we should hope to find nothing.

Note that this argument is Bayesian reasoning about how observations update probabilities; it does not mean that Martian microbes are themselves dangerous. Note also that it presupposes Definition 5.4 as a fact. As Corollary 6.6 shows, the “silence” half of the paradox is adequately explained by insufficient searching, so the argument really bites only on the “absence” half.

  1. G. Cocconi and P. Morrison, “Searching for Interstellar Communications”, Nature 184 (1959), 844–846. — The two-page original paper proposing 1420 MHz1420\ \mathrm{MHz}.
  2. E. M. Jones, “Where Is Everybody?” An Account of Fermi’s Question, Los Alamos National Laboratory report LA-10311-MS (1985). — A primary source collecting interviews with those present at the 1950 lunch.
  3. M. H. Hart, “An Explanation for the Absence of Extraterrestrials on Earth”, Quarterly Journal of the Royal Astronomical Society 16 (1975), 128–135. — The paper that made the paradox rigorous via colonization timescales.
  4. S. Webb, If the Universe Is Teeming with Aliens … WHERE IS EVERYBODY? Seventy-Five Solutions to the Fermi Paradox and the Problem of Extraterrestrial Life, 2nd ed., Springer, 2015. — A comprehensive catalogue of the proposed solutions.
  5. A. Sandberg, E. Drexler and T. Ord, “Dissolving the Fermi Paradox” (2018), arXiv:1806.02404. — Treats the uncertainties of the Drake equation as distributions.
  6. J. T. Wright, S. Kanodia and E. Lubar, “How Much SETI Has Been Done? Finding Needles in the n-Dimensional Cosmic Haystack”, The Astronomical Journal 156 (2018), 260. arXiv:1809.07252 — Quantifies the coverage of the search.

The idea of looking for traces. Radio is emitted only when a civilization decides to transmit. But there is something a civilization cannot help emitting once it grows large: heat. By the second law of thermodynamics, energy that has been used is finally discarded as infrared radiation. This was Freeman Dyson’s point in 1960: a civilization exploiting stellar energy on a large scale should appear anomalously bright in the mid-infrared.

The Kardashev scale. In 1964, Nikolai Kardashev proposed classifying civilizations by the scale of the energy they use. Type I uses all the starlight reaching its planet (about 1016 W10^{16}\ \mathrm{W}), Type II the entire output of its star (about 1026 W10^{26}\ \mathrm{W}), and Type III the output of a whole galaxy (about 1037 W10^{37}\ \mathrm{W}). Humanity has not yet reached Type I; at about 1013 W10^{13}\ \mathrm{W} we sit around Type 0.70.7.

And they were not there. If a Type III civilization existed, its galaxy should stand out in catalogues as faint in visible light and anomalously bright in the mid-infrared. In 2015, Griffith, Wright and collaborators examined about 100,000 galaxies from the catalogue of the WISE infrared satellite and reported finding not one galaxy that reprocesses the bulk of its starlight into the mid-infrared. Their limit was that no galaxy re-radiates more than 8585 % of its starlight.

The Fermi paradox is therefore not confined to our own Galaxy. In none of 100,000 galaxies is there a civilization that has remade its galaxy. The calculation in Proposition 5.1 concerned the interior of the Galaxy, but 13 billion years is also enough to cross the intergalactic distances of a few million light-years. The scale of the question has grown far beyond what Fermi had in mind over lunch.

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